A 5cm square rotates around one side. Find the complete surface of the resulting shape of revolution.

The resulting figure of rotation is a cylinder whose height is equal to the side of the square 5 cm, and the radius of the circle at its base is also 5 cm.

Let us find the area of a circle with a radius of 5 cm, taking Pi – 3.14.

So = 3.14 * 5 * 5 = 78.5 cm2.

Find the circumference of a circle with a radius of 5 cm.

Lo = 2 * 3.14 * 5 = 31.4 cm.

Let us find the area of the lateral surface of the cylinder as the product of the circumference and height.

Sb = 31.4 * 5 = 157 cm2.

Find the total area of the rotation figure.

S = 78.5 * 2 + 157 = 314 cm2.

Answer: the total area of the figure is 314 cm2.