A 6 kW electric crane lifts a 6 t load to a height of 8 m. Determine the lifting time if the installation efficiency is 80%.

N = 6kW = 6000W,
m = 6t = 6000kg,
h = 8m,
t -?
Time is equal to the ratio of work to engine power:
t = A / N,
Mechanical work on lifting the load:
A = m * g * h,
where
g = 10m / s ^ 2 – free fall acceleration;
t = m * g * h / N = 6000 * 10 * 6/6000 = 60s = 1min.



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