A 60 kg person on skates catches a 500 g ball flying horizontally at a speed of 20 m / s. determine the distance to which

| August 12, 2021 | education

A 60 kg person on skates catches a 500 g ball flying horizontally at a speed of 20 m / s. determine the distance to which the person will roll back, if the coefficient of friction is 0.05

These tasks: m1 (the mass of a person on skates) = 60 kg; m2 (mass of the caught ball) = 500 g = 0.5 kg; V2 (initial horizontal speed of the ball) = 20 m / s; μ (coefficient of friction) = 0.05.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Find the speed of a person after contact with the ball: m2 * V2 = (m1 * m2) * V1.2, from where we express: V1.2 = m2 * V2 / (m1 * m2) = 0.5 * 20 / (60 + 0.5) = 0.165 m / s.

2) Find the acceleration of a person: (m1 + m2) * a1.2 = Ftr = μ * (m1 + m2) * g, whence we express: a1.2 = μ * g = 0.05 * 10 = 0.5 m / c2.

3) We calculate the path at rollback: S = V1.22 / 2a = 0.1652 / (2 * 0.5) = 0.0273 m.

Answer: A person on skates should roll back 0.0273 m.



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