A 60K file is transferred over the connection at 1400 bps. Determine how many Kbytes

A 60K file is transferred over the connection at 1400 bps. Determine how many Kbytes more can be transferred in the same time at a speed of 1680 bits per second.

First, let’s find the time of transfer of information (file) through this type of connection.

t = I / v = 60 kB / 1400 bit / s = 60 * 1024 * 8 bit / 1400 bit / s = 351.085714 sec.

Now let’s determine the size of the file that can be transferred in the same time at a connection speed of 1680 bps.

I = v * t = 1680 bit / s * 351.085714 s = 589824 bit.

Let’s translate the found value into more significant information units.

589824 bits = 589824/8 bytes = 73728 bytes = 73728/1024 kB = 72 kB.

Answer: I = 72 KB.