A 64-character alphabet was used to write the text. How much information in bytes does 10 pages

A 64-character alphabet was used to write the text. How much information in bytes does 10 pages of text contain if each page contains 32 lines of 64 characters per line?

To encode one character of the alphabet, consisting of 64 characters, 6 bits are required (2 ^ 6 = 64). This code allows 64 possible states to be encoded.
One page of text contains 64 characters, therefore, to store such a string, 64 x 6 = 384 bits are required.
One page contains 32 terms. Thus, storing the entire page would require 384 x 32 = 12288 bits.
The text consists of 10 pages, so it needs 12288 x 10 = 122880 bits to store it.
One byte contains 8 bits, therefore, 122880 bits = 15360 bytes.
Answer: the text contains 15360 bytes of information.