A bag weighing 100 kg is thrown from above into an open car moving by inertia at a speed of 36 km / h.
| June 9, 2021 | education
A bag weighing 100 kg is thrown from above into an open car moving by inertia at a speed of 36 km / h. How will the speed of the car change and what will be equal to? Vehicle weight 1000 kg.
Data: V (initial vehicle speed) = 36 km / h = 10 m / s; m1 (vehicle weight) = 1000 kg; m2 (bag weight) = 100 kg; V2 (initial speed of the bag) = 0 m / s.
Momentum conservation law:
m1 * V1 + m2 * V2 = (m1 + m2) * U1.2.
m1 * V1 = (m1 + m2) * U1.2.
U1.2 = m1 * V1 / (m1 + m2).
U1.2 = 1000 * 10 / (1000 + 100) = 9.09 m / s (32.7 km / h).
Change (decrease) in speed: 10 – 9.09 = 0.91 m / s (3.3 km / h).
Answer: The vehicle speed will decrease by 0.91 m / s (3.3 km / h) and become 9.09 m / s (32.7 km / h).
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