A ball fell from a height of 25 meters for 2.5 seconds, what is its resistance force if the mass is 500 grams?

Let us consider the motion of the ball as uniformly accelerated rectilinear, with zero initial velocity. Let’s find the acceleration with which the ball fell:

S = at ^ 2/2;

a = 2S / t ^ 2 = 2 * 25 / 2.52 = 8 m / s2;

The resultant forces acting on the ball will be equal to:

F = a * m = 8 * 0.5 = 4 H;

Let us find the force of resistance of the medium as the difference between the force of gravity and the resultant:

Fc. = Ft. – F = m * g – F = 0.5 * 9.8 – 4 = 0.9 N.

Answer: Fsopr. = 0.9 N.