# A ball fell from a height of 25 meters for 2.5 seconds, what is its resistance force if the mass is 500 grams?

October 3, 2021 | education

| Let us consider the motion of the ball as uniformly accelerated rectilinear, with zero initial velocity. Let’s find the acceleration with which the ball fell:

S = at ^ 2/2;

a = 2S / t ^ 2 = 2 * 25 / 2.52 = 8 m / s2;

The resultant forces acting on the ball will be equal to:

F = a * m = 8 * 0.5 = 4 H;

Let us find the force of resistance of the medium as the difference between the force of gravity and the resultant:

Fc. = Ft. – F = m * g – F = 0.5 * 9.8 – 4 = 0.9 N.

Answer: Fsopr. = 0.9 N.

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