A ball having a radius of 10 cm is connected by a thin wire to a ball with a radius of 2 cm.

A ball having a radius of 10 cm is connected by a thin wire to a ball with a radius of 2 cm. The balls were given a charge of 0.06 μC. Determine the charge and potential of each ball.

given
R1 = 10 cm = 0.1 m
R2 = 2 cm = 0.02 m
q = 0.06 μC = 6 * 10 to the power (- 8) С
k = 9 * 10 to the 9th power
find the charge q1 and q2
potential φ1 and φ2

decision
q = q1 + q2 = q1 * (1 + q2 / q1)
φ1 = φ2
then
k * q1 / R1 = k * q2 / R2
q1 / R1 = q2 / R2
q2 / q1 = R2 / R1
from here
q1 = q * (1 + R2 / R1) to the power (- 1) = 6 * 10 to the power (- 8) * (1 + 0.02 m / 0, 1 m) = 5 * 10 to the power (- 8 ) FROM
q2 = q – q1 = 6 * 10 to the power (- 8) С – 5 * 10 to the power (- 8) С = 1 * 10 to the power (- 8) С
φ1 = k * q1 / R1 = 9 * 10 to the degree of 9 * 5 * 10 to the degree (- 8) C / 0, 1 = 4. 5 * 10 to the power of 3 V
φ2 = k * q2 / R2 = 9 * 10 to the power of 9 * 1 * 10 to the power (- 8) C / 0, 02 = 4. 5 * 10 to the power of 3 V



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