A ball is thrown vertically downward from a height of 2.4 meters at a speed of 1 m / s. What is the speed at the moment of falling?

These tasks: h (height from which the ball was thrown) = 2.4 m; V0 (throw speed) = 1 m / s (downward velocity vector) = 1 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To calculate the speed of the taken ball at the moment of falling, we apply the formula: h = (V ^ 2 – V0 ^ 2) / 2a = (V ^ 2 – V0 ^ 2) / 2g, whence V = √ (h * 2g + V0 ^ 2 ).

Calculation: V = √ (2.4 * 2 * 10 + 1 ^ 2) = √ (48 + 1) = 7 m / s.

Answer: At the moment of falling, the taken ball reached a speed of 7 m / s.