A ball thrown from a 5 m high tower fell at a distance of 7.5 m from its base. What is the final velocity of the ball?
| November 26, 2020 | education
Ball fall time t = √ (2 * h / g) = √ (10 / 9.8) ≈ 1.01 s.
The horizontal speed of the ball is Vg = 7.5 / 1.01 = 7.425 m / s.
The vertical speed of the ball at the moment of falling Vw = √ (2 * g * h) = √ 98 ≈ 9.9 m / s.
The speed at the moment of falling V = √ (Vg2 + Vw2) = √ (9.92 + 7.4252) = 12.375 m / s.
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