A ball weighing 0.1 kg moves at a speed of 5 m / s. After hitting the wall, it began to move in the opposite direction at a speed

| January 13, 2021 | education

A ball weighing 0.1 kg moves at a speed of 5 m / s. After hitting the wall, it began to move in the opposite direction at a speed of 4 m / s. What is the change in momentum of the ball?

Given:
m = 0.1 kilogram is the mass of the ball;
v1 = 5 m / s – the speed of the ball before colliding with the wall;
v2 = 4 m / s – the speed of the ball after collision with the wall (in the opposite direction);
It is required to determine dP (kg * m / s) – the change in the ball’s momentum.
The momentum of the ball before colliding with the wall is:
P1 = m * v1 = 0.1 * 5 = 0.5 kg * m / s.
The momentum of the ball after colliding with the wall is:
P2 = m * v2 = 0.1 * 4 = 0.4 kg * m / s.
Then the change in momentum will be equal to:
dP = P – P2 = 0.5 – 0.4 = 0.1 kg * m / s.
Answer: the change in the momentum of the ball is 0.1 kg * m / s.



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