A ball weighing 0.1 kg was thrown vertically upward. As a result, the ball rose to a height of 4 m and then fell back

A ball weighing 0.1 kg was thrown vertically upward. As a result, the ball rose to a height of 4 m and then fell back to the ground. What is the work done by gravity along the entire path of the ball?

Let’s designate all forces. So the work of the force of gravity up A1, the work of the force of gravity down – A2, the total work that the force of gravity has done – A3.
m = 0.1 kg, h = 4 m, g = 10m / s ^ 2.
A1 = – m * g * h;
A2 = m * g * h;
A3 = m * g * (h-h);
A1 = -0.1 * 10 * 4 = – 4J;
A2 = 0.1 * 10 * 4 = 4J;
A3 = 0.1 * 10 * (4-4) = 0 J.
In general, since the action of gravity has passed in a circle, the model of the work of gravity will be as follows: upwards it loses 4J, returns down 4J, and in general 0J is spent.