A ball weighing 0.5 kg after a blow of 0.02 s duration acquires a speed of 10 m / s. Determine the average impact force.

m = 0.5 kg.

t = 0.02 s.

V0 = 0 m / s.

V = 10 m / s.

Fср -?

According to Newton’s 2 law, the force Fav, which acts on the ball, is equal to the product of its mass m by the acceleration a, which this force imparts to it: Fav = m * a. Force Fav directed in the same direction as acceleration a.

The acceleration of the body a shows how the speed of the ball changes over time. The acceleration of the ball is expressed by the formula: a = (V – V0) / t.

Fav = m * (V – V0) / t.

Since the ball was initially at rest, then V0 = 0 m / s.

Fav = m * V / t.

Fav = 0.5 kg * 10 m / s / 0.02 s = 250 N.

Answer: the average force of impact on the ball is Fav = 250 N.



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