A ball weighing 0.5 kg is thrown vertically upward at a speed of 10 m / s. What is the potential energy

A ball weighing 0.5 kg is thrown vertically upward at a speed of 10 m / s. What is the potential energy of the ball with the highest lifting point.

When the ball reaches its maximum height, its speed will be equal to zero and it will begin to free fall downward. Hence:
h = V0 ^ 2 / 2g, where V0 is the initial velocity of the ball, m / s; g – acceleration of gravity (g = 10 m / s ^ 2).
h = 10 ^ 2 / (2 * 10) = 100/20 = 5 m.Check m = ((m / s) ^ 2) / (m / s ^ 2) = (m ^ 2 / s ^ 2) / (m / s ^ 2) = m.
It follows from this that the potential energy of the ball at a height of 5 m is equal to:
Ep = mgh, where m is the mass of the ball, g is the acceleration of gravity, h is the height the ball has risen.
Ep = 0.5 * 10 * 5 = 25 J.