A ball weighing 1 kg falls from a height of 2 m. Determine the change in the kinetic energy

A ball weighing 1 kg falls from a height of 2 m. Determine the change in the kinetic energy of the ball in the first and second half of the path.

According to the law of conservation of energy:
Ek = -Ep.
Potential energy:
En = m * g * h.
Potential energy change:
ΔЕп = m * g * Δh.
Δh1 = 2-1 = 1 m.
Δh2 = 1-0 = 1 m.
Energy change at the first stage of the path:
ΔEp1 = m * g * Δh1 = 1 * 9.8 * 1 = 9.8 J.
Energy change at the second stage of the path:
ΔEn2 = m * g * Δh2 = 1 * 9.8 * 1 = 9.8 J.
Answer: ΔEp1 = ΔEp2 = 9.8 J.