A ball weighing 100 g, flying at a speed of 1.5 m / s, is caught on the fly. What is the average force

A ball weighing 100 g, flying at a speed of 1.5 m / s, is caught on the fly. What is the average force of the ball acting on the hand if its speed decreases to zero in a time equal to 0.03 s?

m = 100 g = 0.1 kg.

V0 = 1.5 m / s.

V = 0 m / s.

t = 0.03 s.

Fr -?

According to Newton’s 3 laws, the force of action is equal to the force of reaction. The force with which the ball acts on the hand Fr is equal in magnitude and opposite to the directional force with which the hand acts on the ball Fm: Fr = Fm.

According to Newton’s 2 law, the force Fm, which acts on the ball, is equal to the product of its mass m by the acceleration a: Fmr = m * a.

The acceleration of the ball a shows how its speed changes over time. The acceleration of the ball is expressed by the formula: a = (V0 – V) / t.

Fm = m * (V0 – V) / t.

Since the ball in the hand has stopped, then V = 0 m / s.

Fm = m * V0 / t.

Fр = m * V0 / t.

Fr = 0.1 kg * 1.5 m / s / 0.03 s = 5 N.

Answer: the ball acts on the hand with a force of Fр = 5 N.