A ball weighing 150 g is suspended on a silk thread and has a charge of 10 nC at a distance of 30 cm from the bottom

| April 27, 2021 | education

A ball weighing 150 g is suspended on a silk thread and has a charge of 10 nC at a distance of 30 cm from the bottom, another ball is placed, what should be the charge of this ball, so that the tension force of the thread is halved.

To solve this problem, let us find the force, reduced by 2 times, than the tension force of the thread holding the suspended ball. Where G = 9.8 m / s2 is the acceleration of gravity at the earth’s surface.

F = 0.15 kg * G = 0.15 kg * 9.8 m / s2 = 1.47 N / 2 = 0.735 N.

We use the formula to find the force of interaction of two charges.

F = (Q * q) / R ^ 2. From here we find the required charge Q.

Q = (F * R ^ 2) / q = (0.735 N * 0.09 C) / 10 * 10 ^ -9 C = 0.06615 N * C / 10 * 10 ^ -9 C = 6615000 C.

Answer: the charge is Q = 6615000 Cl.



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