A ball weighing 200 g falls on a horizontal platform. The moment of impact, the speed of the ball is 5 ms.

univerkov | December 14, 2020 | education

A ball weighing 200 g falls on a horizontal platform. The moment of impact, the speed of the ball is 5 ms. Determine the change in impulse with an absolutely elastic impact.

Given:
m = 200G
v = 5m / s
Find: p =?
SI: m = 0.2kg
Decision:
Pulse measurement:
p = p1-p2 = mv – (- mv) = 2 * 0.2 * 5 = 2 kg * m / s
Answer: 2kg * m / s

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