A ball weighing 3 kg floats on the surface of the water being immersed in it by the value of its radius.

A ball weighing 3 kg floats on the surface of the water being immersed in it by the value of its radius. Determine the density of the ball.

To begin with, I want to tell you about the formula for calculating the force of Archimedes. F = (density) * g * V. Since the ball is in equilibrium, the force of attraction: F = mg is equal to F = (density) * g * V. We get the equation mg = (density) * g * V. express the density from the equation. We get the following equation: (density) = mg / gV. g cancels out and we get (density) = m / V. The volume of the sphere is 4/3 * 3.14 * R ^ 3. Since only half of the sphere is lowered into the water, the volume we need is 4/6 * 3.14 * R ^ 3. We substitute it in the initial formula and calculate it on the calculator. (density) = 9 / (8 * 3.14 * R ^ 3)



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