A ball weighing 8 kg rolls at a speed of 1.5 m / s and hits another ball which is 4 times lighter than the first.

A ball weighing 8 kg rolls at a speed of 1.5 m / s and hits another ball which is 4 times lighter than the first. What speed will the second ball gain? What is the momentum of the balls?

According to the law of conservation of momentum p1v1 = p2v2.
Then we substitute the known mass and velocity of the first ball and the ratio of the masses of the balls
8 * 1.5 = 8 * x / 4, x = 6 m / s.
p (balls) = 12 n * m / s



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