A bar was suspended from a spring with a stiffness of 400 N / m, under the weight of which the spring stretched by 10 cm.
| November 20, 2020 | education
A bar was suspended from a spring with a stiffness of 400 N / m, under the weight of which the spring stretched by 10 cm. What elastic force appeared in the spring?
The elastic force is equal to the k-stiffness of the body multiplied by the l-value of the deformation – F = kl. l = 10cm = 0.1m; k = 400H / m.
F = 0.1×400 = 40 (H).
Answer: 40 N.
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