A bar weighing 0.4 kg during a collision with a bar weighing 1.0 kg moved with an acceleration of 1.5

A bar weighing 0.4 kg during a collision with a bar weighing 1.0 kg moved with an acceleration of 1.5 m / s ^ 2. with what acceleration did the second bar move at this time?

To find the value of the acceleration of the second bar during a collision, we use the equality: Fb1 = Fb2 and mb1 * ab1 = mb2 * ab2, whence we express: ab2 = mb1 * ab1 / mb2.

Variables: mb1 – mass of the first bar (mb1 = 0.4 kg); ab1 – acceleration of the first bar (ab1 = 1.5 m / s2); mb2 is the mass of the second bar (mb2 = 1 kg).

Let’s perform the calculation: ab2 = mb1 * ab1 / mb2 = 0.4 * 1.5 / 1 = 0.6 m / s2.

Answer: The second bar during the collision had to move with an acceleration of 0.6 m / s2.