A bar weighing 1 kg weighs 8 N in water, and 6 N in some solution. Determine the density of the solution.

Data: m (bar weight) = 1 kg; P1 (weight of the bar in water) = 8 N; P2 (weight in some solution) = 6 N.

Constants: g (acceleration due to gravity) ≈ 10 m / s2; ρw (water density) = 1000 kg / m3.

1) The volume of the indicated bar: P1 = Ft – Fa1 = m * g – ρw * g * V, whence we express: V = (m * g – P1) / (ρw * g) = (1 * 10 – 8) / ( 1000 * 10) = 2 * 10-4 m3.

2) The density of the solution: P2 = Fт – Fa2 = m * g – ρх * g * V, whence we express: ρх = m * g – P2) / (g * V) = (1 * 10 – 6) / (10 * 2 * 10-4) = 2 * 103 kg / m3.

Answer: The density of the solution is 2 * 103 kg / m3.



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