# A bar weighing 2 kg moves on a horizontal surface under the action of a force of 1 N.

A bar weighing 2 kg moves on a horizontal surface under the action of a force of 1 N. The initial velocity of the bar is zero. What speed will it acquire in 5 s if the force is directed horizontally?

To find the speed acquired by the specified bar in 5 seconds of accelerated movement, we use the formula: V = a * t = (F / m) * t = F * t / m.

Variables: F – force acting on the specified bar (F = 1 N); m – mass (m = 2 kg); t is the duration of the movement of the bar (t = 5 s).

Calculation: V = F * t / m = 1 * 5/2 = 2.5 m / s.

Answer: After 5 seconds, the indicated bar will have a speed of 2.5 m / s.

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