A bar weighing 200 g slides on ice to determine the sliding friction force acting on the bar if the coefficient of sliding friction of the bar on ice is 0.1.
m = 200 g = 0.2 kg.
g = 10 m / s2.
μ = 0.1.
When sliding on the ice surface, 3 forces act on a bar: m * g is the force of gravity directed vertically downward, N is the reaction force of the ice surface directed vertically upward, Ffr is the sliding friction force directed in the opposite direction of motion ..
m * a = m * g + N + Ftr – 2 Newton’s law.
ОХ: m * a = Ftr.
OU: 0 = – m * g + N.
N = m * g.
The sliding friction force Ftr is determined by the formula: Ftr = μ * N = μ * m * g.
Ftr = 0.1 * 0.2 kg * 10 m / s2 = 0.2 N.
Answer: when the bar slides over the ice surface, the sliding friction force Ftr = 0.2 N. acts on it.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.