# A bar weighing 200 g slides on ice to determine the sliding friction force acting

**A bar weighing 200 g slides on ice to determine the sliding friction force acting on the bar if the coefficient of sliding friction of the bar on ice is 0.1.**

m = 200 g = 0.2 kg.

g = 10 m / s2.

μ = 0.1.

Ftr -?

When sliding on the ice surface, 3 forces act on a bar: m * g is the force of gravity directed vertically downward, N is the reaction force of the ice surface directed vertically upward, Ffr is the sliding friction force directed in the opposite direction of motion ..

m * a = m * g + N + Ftr – 2 Newton’s law.

ОХ: m * a = Ftr.

OU: 0 = – m * g + N.

N = m * g.

The sliding friction force Ftr is determined by the formula: Ftr = μ * N = μ * m * g.

Ftr = 0.1 * 0.2 kg * 10 m / s2 = 0.2 N.

Answer: when the bar slides over the ice surface, the sliding friction force Ftr = 0.2 N. acts on it.