A bar weighing 5 kg rests on a rough horizontal table. The coefficient of friction between
| April 6, 2021 | education
A bar weighing 5 kg rests on a rough horizontal table. The coefficient of friction between the surface of the bar and the surface of the table is 0.2. This bar is acted upon by a horizontally directed force of 2.5 N. What is the modulus of the resulting friction force?
The friction force Ft depends on the reaction force N acting on the bar and on the friction coefficient μ:
Fт = μN.
The reaction of the table N in absolute value is equal to the body weight P:
| N | = | P | = mg;
Fт = μmg = 0.2 * 5 kg * 9.6 m / s2 = 9.6 N.
Answer: The modulus of friction force is 9.6 N.
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