A battery of elements with EMF = 21 V and an internal resistance of 0.5 Ohm is connected to an external

| August 1, 2021 | education

A battery of elements with EMF = 21 V and an internal resistance of 0.5 Ohm is connected to an external circuit consisting of three parallel-connected conductors with resistances of 2, 6 and 12 Ohms. Determine the current in a conductor with a resistance of 6 ohms

Problem data: ε (EMF of the indicated battery of cells) = 21 V; r (battery resistance) = 0.5 ohm; resistance of conductors from the external circuit: R1 = 2 Ohm; R2 = 6 ohms; R3 = 12 ohms.

1) External resistance for the specified battery of cells: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 = 1/2 + 1/6 + 1/12 = 0.75 and R = 1 / 0.75 = 1 , 33 (3).

2) Current in the circuit: I = ε / (r + R) = 21 / (0.5 + 1.33 (3)) = 11.455 A.

3) Voltage on the external circuit: U = I * R = 11.455 * 1.33 (3) = 15.273 V.

4) Current in the second conductor from the external circuit: I2 = U / R2 = 15.273 / 6 = 2.55 A.

Answer: The current in the second conductor from the external circuit is 2.55 A.



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