A battery with an EMF of 2 V and an internal resistance of 0.2 Ohm is closed with a resistance of 4.8 Ohm.

univerkov | January 9, 2021 | education

A battery with an EMF of 2 V and an internal resistance of 0.2 Ohm is closed with a resistance of 4.8 Ohm. Find the amperage on the outside of the circuit.

First, we need to find the total amperage
I = U / (r + R) = 0.4A
voltage drop across external load
U = R * I = 4.8 * 0.4 = 1.92 V
Power: P = I * U = 1.92 * 0.4 = 0.768W
Answer: 0.768W

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