A battery with an emf of 6V and an internal resistance of 1.5 ohms feeds an external circuit

univerkov | May 22, 2021 | education

A battery with an emf of 6V and an internal resistance of 1.5 ohms feeds an external circuit consisting of two parallel-connected conductors with a resistance of 2 and 8 ohms. Determine the current in the external circuit.

To find the value of the current in the presented circuit, we will use the formula: I = ε / (r + R) = ε / (r + (R2 * R1) / (R2 + R1)).

Variables: ε – EMF of the used battery (ε = 6 V); r – internal resistance (r = 1.5 Ohm); R2 is the resistance of the second of the taken conductors (R2 = 8 Ohm); R1 is the resistance of the first taken conductor (R1 = 2 ohms).

Calculation: I = ε / (r + (R2 * R1) / (R2 + R1)) = 6 / (1.5 + (2 * 8) / (2 + 8)) = 1.94 A.

Answer: The current in the presented circuit is 1.94 A.

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