A beaker filled to the brim with alcohol has a mass of 500 grams, not even a zorka without alcohol has a mass

A beaker filled to the brim with alcohol has a mass of 500 grams, not even a zorka without alcohol has a mass of 100 grams what volume the beaker intervenes.

Given:
m1 = 500 grams = 0.5 kilograms – the mass of the beaker with alcohol;
m2 = 100 grams = 0.1 kilogram – the mass of the beaker without alcohol;
ro = 800 kg / m3 is the density of alcohol.
It is required to determine V (cubic meter) – how much the beaker holds.
Find the mass of alcohol:
m = m1 – m2 = 0.5 – 0.1 = 0.4 kilograms.
Then the volume occupied by alcohol (and hence the volume of the beaker) is equal to:
V = m / ro = 0.4 / 800 = 0.0005 cubic meters = 0.5 liters.
Answer: The beaker holds a volume of 0.5 liters (0.0005 cubic meters).



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