A bisector BF is drawn in a right-angled triangle ABC with a right angle A and AF is 10 cm.
| August 7, 2021 | education
A bisector BF is drawn in a right-angled triangle ABC with a right angle A and AF is 10 cm.Find the distance from F to line BC
The distance from point F to the hypotenuse BC is the perpendicular FH to BC.
Triangles ABF and BHF are rectangular, in which the hypotenuse BF is common, and the angle ABF = HBF since BF, by condition, is the bisector of angle B.
Then right-angled triangles ABF and BHF are equal in hypotenuse and acute angle, and then FH = AF = 10 cm.
Answer: From point F to BC 10 cm.
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