A bisector CK is drawn in a right-angled triangle ABC by a right angle B, with KB = 14 cm.

A bisector CK is drawn in a right-angled triangle ABC by a right angle B, with KB = 14 cm. Find the distance from point K to line AC.

The distance from point K to line AC is the perpendicular, KH, drawn to the AC side.

Then triangles CBK and CHK are rectangular, in which the hypotenuse of AK is common.

СK, by condition, is the bisector of angle С, then the angle KСВ = KСН.

Then the triangles ВСK and НСK are equal in hypotenuse and acute angle, and therefore KН = ВK = 14 cm.

Answer: From point K to straight AC 14 cm.