A block of balsa wood, with a density of 0.25g / cm ^ 3, floats in fresh water. What part of the bar is
| April 29, 2021 | education
A block of balsa wood, with a density of 0.25g / cm ^ 3, floats in fresh water. What part of the bar is submerged in water?
To determine the value of a part of a cork block immersed in water, we use the equation: Fт = Fa; m * g = ρw * g * Vpod; ρпр * V * g = ρв * g * Vpod, whence we express: Vпр / V = ρпр * g / ρв * g = ρпр / ρв.
Constants: ρпр – density of a balsa tree (according to the condition ρпр = 0.25 g / cm3 = 250 kg / m3); ρw is the density of fresh water (ρw = 1000 kg / m3).
Calculation: Vp / V = ρpr / ρv = 250/1000 = 1/4.
Answer: 1/4 of a cork block is immersed in fresh water.
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