# A block weighing 1 kg is evenly pulled over the table, applying a force equal to 3.5 N. What force must

August 24, 2021 | education

| **A block weighing 1 kg is evenly pulled over the table, applying a force equal to 3.5 N. What force must be applied to lift this block above the table?**

m = 1 kg.

g = 9.8 m / s2.

Fhor = 3.5 N.

Fvert -?

To lift the bar, according to 1 Newton’s law, a vertical force Fvert is required, which will compensate for the force of gravity Ft, which acts on the bar: Fvert = Ft.

The force of gravity Ft is determined by the formula: Ft = m * g, where m is the mass of the bar, g is the acceleration of gravity.

Fvert = m * g.

Fvert = 1 kg * 9.8 m / s2 = 9.8 N.

Answer: in order to raise the bar above the table, it is necessary to apply vertical force Fvert = 9.8 N.

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