A block weighing 1 kg is evenly pulled over the table, applying a force equal to 3.5 N. What force must
| August 24, 2021 | education
A block weighing 1 kg is evenly pulled over the table, applying a force equal to 3.5 N. What force must be applied to lift this block above the table?
m = 1 kg.
g = 9.8 m / s2.
Fhor = 3.5 N.
Fvert -?
To lift the bar, according to 1 Newton’s law, a vertical force Fvert is required, which will compensate for the force of gravity Ft, which acts on the bar: Fvert = Ft.
The force of gravity Ft is determined by the formula: Ft = m * g, where m is the mass of the bar, g is the acceleration of gravity.
Fvert = m * g.
Fvert = 1 kg * 9.8 m / s2 = 9.8 N.
Answer: in order to raise the bar above the table, it is necessary to apply vertical force Fvert = 9.8 N.
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