A block weighing 100 g, suspended on a light thread, is lifted vertically upward with an acceleration

A block weighing 100 g, suspended on a light thread, is lifted vertically upward with an acceleration equal to 1 m / s2 in modulus and directed upward. The tensile force modulus of the thread is equal.

Task data: m (mass of the taken bar) = 100 g (0.1 kg); a (acceleration with which the bar is lifted up) = 1 m / s2.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The tensile force modulus of the thread can be calculated by the formula: T = m * a + Fт = m + a + m * g = m * (g + a).

Calculation: T = 0.1 * (10 + 1) = 1.1 N.

Answer: The module of the tension force of the thread when lifting the bar is 1.1 N.