# A block weighing 100 g, suspended on a light thread, moves upward with such an acceleration

A block weighing 100 g, suspended on a light thread, moves upward with such an acceleration that its weight is three times greater than at rest. The acceleration module is …

To find the value of the acceleration modulus of the specified bar, we use the formula: Pк = m * (g + a), whence we express: a = Pк / m – g.

Constants and variables: Рк – the considered weight of the bar = 3Рн = 3 * m * g; g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: a = Pк / m – g = 3 * m * g / m – g = 3g – g = 2g = 2 * 10 = 20 m / s2.

Answer: The module of acceleration of the indicated bar is equal to 20 m / s2.

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