A block with a mass of m = 2 kg is suspended from a dynamometer. A thread with a load of m1 = 2 kg and m 2 = 4 kg

| November 17, 2020 | education

A block with a mass of m = 2 kg is suspended from a dynamometer. A thread with a load of m1 = 2 kg and m 2 = 4 kg is thrown over the load. What force the dynamometer will show during the movement of loads.

the blocks will be affected by the force of gravity and the force of the simplification of the thread (T)

acceleration when driving will be the same
because the thread is the same and the same T1 = T2 = T

dynamometer will show F = 2T
according to newton’s second law
directly in projections on the op-amp
m1g-T = -ma
m2g-t = m2a
now subtract the first from the second
m2g – t – m1g + t = m2a + m1a
T will shrink
m2g-m1g = a (m2 + m1)
find acceleration

a = g (m2-m1) / m2 + m1

and now we substitute everything into any of the equations

m2g-T = m2a

-T = m2a + m2g
T = m2 (g-a)
F = 2T

whole decision
substitute the values yourself



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