A body falls from a height of 10 m. At what speed will it fall to the ground?

To calculate the speed of a body at the moment of touching the ground, we apply the following formula: h = S = (V ^ 2 – V0 ^ 2) / 2a and V = √ (2a * h + V0 ^ 2).

Variables: a – acceleration of a certain body (a = g (acceleration of gravity) ≈ 10 m / s2); h – height (h = 10 m); V0 is the speed before the start of the fall (V0 = 0 m / s).

Let’s perform the calculation: V = √ (2a * h + V0 ^ 2) = √ (2 * 10 * 10 + 0 ^ 2) = 14.14 m / s.

Answer: Some body will fall at a speed of 14.14 m / s.