A body immersed in kerosene is subjected to a buoyant force of 8 kN. Determine its volume.

Data: FA – known buoyancy force (FA = 8 kN = 8 * 10 ^ 3 N).

Const: ρк – density of kerosene (according to the condition of the principle ρк = 800 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2).

To find out the required volume of a submerged body, we use the formula: FA = ρк * g * Vx, from where we express: Vx = FA / (ρк * g).

Let’s calculate: Vx = FA / (ρк * g) = 8 * 10 ^ 3 / (800 * 10) = 1 m3.

Answer: The volume of the submerged body, according to the calculation, is 1 m3.