A body measuring 4 x 1 x 0.2 (s) is immersed in oil. What is the Archimedean force acting on the body (oil density 800 kg / m3)

Initial data: the dimensions of the body immersed in oil are 4 x 1 x 0.2 m.
Reference data: g (acceleration due to gravity) ≈ 10 m / s2; by the condition ρн (oil density) = 800 kg / m3.
The Archimedean force that acts on the body in question in oil can be determined by the formula: Fa = ρн * g * V = ρн * g * a * b * c.
Calculation: Fa = 800 * 10 * 4 * 1 * 0.2 = 6400 N.
Answer: E) Archimedean force is equal to 6400 N.