A body moving uniformly accelerated from a state of rest for 10 s travels 38 m of the way.

A body moving uniformly accelerated from a state of rest for 10 s travels 38 m of the way. Which way the body will go in 12 seconds.

Since the motion of the body in question is uniformly accelerated and began from a state of rest, then we can apply the equality: S1 / t1 ^ 2 = a / 2 = S2 / t2 ^ 2, whence we express: S2 = S1 * t2 ^ 2 / t1 ^ 2.

Variables: S1 – initial path of the body (S1 = 38 m); t2 – total time of movement (t2 = 12 s); t1 – initial time of movement (t1 = 10 s).

Calculation: S2 = 38 * 12 ^ 2/10 ^ 2 = 54.72 m.

Answer: In 12 seconds, the body in question should travel a path of 54.72 m.