A body thrown vertically down from a height of 150 m at a speed of 8 m / s, plunged into the ground to a depth of 12 cm.

A body thrown vertically down from a height of 150 m at a speed of 8 m / s, plunged into the ground to a depth of 12 cm.Find the resistance force when the body moves in the ground, considering it constant if the body weight is 2 kg

h = 150 m.
V = 8 m / s.
S = 12 cm = 0.12 m.
m = 2 kg.
g = 9.8 m / s ^ 2.
F -?
We will use the law of conservation of total mechanical energy. At the moment of throwing, the body has total mechanical energy E, which consists of potential En and kinetic Ek.
E = Ek + En.
Potential energy is determined by the formula: En = m * g * h.
The kinetic energy is determined by the formula: Ek = m * V ^ 2/2.
All this energy is spent on performing work by friction force.
E = A.
The work of the friction force is determined by the formula: A = F * S.
m * g * h + m * V ^ 2/2 = F * S.
F = (m * g * h + m * V ^ 2/2) / S.
F = (2 kg * 9.8 m / s ^ 2 * 150 m + 2 kg * (8 m / s) ^ 2/2) / 0.12 m = 25033 N.
Answer: resistance force in soil F = 25033 N.