A body thrown vertically upward from point A fell into the mine.

A body thrown vertically upward from point A fell into the mine. What are the path traveled by the body and the modulus of displacement, if AB = 15cm, BC = 18?

Given:

AB = 15 cm = 0.15 meters – the distance from point A to point B;

BC = 18 cm = 0.18 meters – the distance from point B to point C.

It is required to determine the traversed path S (meter) and displacement L (meter).

From the condition of the problem it is clear that the body was thrown from point A, reached the maximum height B and fell into the mine at point C. Since the distance from point A to B is 15 cm, and from point B to point C is 18 cm, then:

Distance covered S = AB + BC = 0.15 + 0.18 = 0.33 meters;

Moving L = BC – AB = 0.18 – 0.15 = 0.03 meters.

Answer: The distance traveled is 0.33 meters (33 centimeters), the displacement is 0.03 meters (3 centimeters).