A body weighing 0.1 kg falls freely within 5 s. What is the kinetic energy of the body at the end of the fall?

According to the law of conservation of energy: Ek = En => Ek = mgh since the body falls freely, which means the initial velocity is zero, and, therefore, S = h = gt ^ 2/2. Ek = m * g ^ 2 * t ^ 2/2 = 0.1 * 100 * 25/2 = 125 J



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