A body weighing 0.3 kg moves in a straight line along a horizontal plane. The work done by gravity

A body weighing 0.3 kg moves in a straight line along a horizontal plane. The work done by gravity when moving a body by 20 cm is …

m = 0.3 kg.

g = 10 N / kg.

S = 20cm = 0.2m.

At -?

According to the definition, the mechanical work A of the force F is determined by the formula: A = F * S * cosα, where S is the displacement of the body under the action of the force, ∠α is the angle between the displacement S and the direction of action of the force F.

The force of gravity Ft is always directed vertically downward and is determined by the formula: Ft = m * g, where m is the mass of the body, g is the acceleration of gravity.

Since the body moves horizontally, and the force of gravity is directed vertically, the angle between them is ∠α = 90.

cos90 = 0.

At = Ft * S * cosα = m * g * S * cos90 = 0.

Answer: with the horizontal movement of the body, the work of gravity Am is 0: Am = 0.