A body weighing 0.5 kg falls freely without initial velocity. What is the impulse of the body 1 s after the start of the fall?

To find the momentum of the body after 1 second of falling, we will use the formula: P = m * V = m * (V0 + g * t) = m * (0 + g * t) = m * g * t.

Constants and variables: m is the mass of the falling body (m = 0.5 kg); g – acceleration due to gravity (g ≈ 10 m / s2); t – considered fall time (t = 1 s).

Calculation: P = m * g * t = 0.5 * 10 * 1 = 5 kg * m / s.

Answer: After 1 second of free fall, the sought impulse of the body will be 5 kg * m / s.