A body weighing 0.5 kg is thrown at a speed of 20 m / s at an angle of 30 degrees to the horizon.

A body weighing 0.5 kg is thrown at a speed of 20 m / s at an angle of 30 degrees to the horizon. Determine the highest flight altitude.

m = 0.5 kg.
∠α = 30 °.

V0 = 20 m / s.

g = 10 m / s2.

h -?

The motion of a body can be divided into two types: horizontally, it moves uniformly with a speed Vх = V0 * cosα, vertically uniformly accelerated with gravitational acceleration g and an initial speed V0у = V0 * sinα.

At the maximum height, the body will stop, so the maximum height is expressed by the formula: h = V0у ^ 2/2 * g = (V0 * sinα) ^ 2/2 * g.

h = (20 m / s * sinα 30 °) ^ 2/2 * g = 5 m.

Answer: the maximum flight height of the body is h = 5 m.