A body weighing 0.5 kg, thrown vertically upward at a speed of 20 m / s

A body weighing 0.5 kg, thrown vertically upward at a speed of 20 m / s, rose to a height of 15 m. Determine the average value of the air resistance

To find the average value of the air resistance force, we use the equality: A = ΔE and Fc * h = m * V ^ 2/2 – m * g * h, whence we express: Fc = m * (V ^ 2/2 – g * h ) / h.

Constants and variables: m – the mass of the thrown body (m = 0.5 kg); V – vertical throw speed (V = 20 m / s); g – acceleration due to gravity (g ≈ 10 m / s2); h – lifting height (h = 15 m).

Calculation: Fc = m * (V ^ 2/2 – g * h) / h = 0.5 * (20 ^ 2/2 – 10 * 15) / 15 = 1.67 N.

Answer: Air acted on the thrown body with an average force of 1.67 N.