# A body weighing 1.2 kg acquired a speed of 12 m / s at a distance of 2.4 km under the action

A body weighing 1.2 kg acquired a speed of 12 m / s at a distance of 2.4 km under the action of a force of 16N. Find the initial velocity of the body And then how?

To find the initial speed of a given body, we use the formula: S = (Vk ^ 2 – Vn ^ 2) / 2a = (Vk ^ 2 – Vn ^ 2) / (2F / m) = m * (Vk ^ 2 – Vn ^ 2 ) / 2F, whence we express: Vн = √ (Vк ^ 2 – S * 2F / m).

Values of variables: Vк – acquired speed (Vк = 12 m / s); S – distance traveled (S = 2.4 m); F – acting force (F = 16 N); m – body weight (m = 1.2 kg).

Calculation: Vн = √ (Vк ^ 2 – S * 2F / m) = √ (12 ^ 2 – 2.4 * 2 * 16 / 1.2) = √80 = 8.94 m / s.

Answer: The initial speed was 8.94 m / s.

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