A body weighing 1.6 kg, thrown vertically upwards, fell to the ground in 3 seconds, to determine the kinematic
| September 20, 2021 | education
A body weighing 1.6 kg, thrown vertically upwards, fell to the ground in 3 seconds, to determine the kinematic eneology at the moment of impact by air resistance.
To find the kinetic energy at the moment of impact, we use the formula: Ek = m * V² / 2 = m * (g * t1) ² / 2 = m * (g * t / 2) ² / 2.
Constants and variables: m – the mass of the thrown body (m = 1.6 kg); g – acceleration due to gravity (g ≈ 10 m / s2); t – time of rise and fall of the body (t = 3 s).
Calculation: Ek = m * (g * t / 2) ² / 2 = 1.6 * (10 * 3/2) ² / 2 = 180 J.
Answer: The kinetic energy at the moment of impact was 180 J.
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